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Organic synthesis

OCR Year 1 · written to the mark scheme

In a nutshell

Organic synthesis is about making a target compound on purpose: choosing the reactions, carrying them out with the right apparatus, and purifying the product.

This subtopic pulls together every reaction in Module 4. You need the practical techniques (reflux, distillation, separating funnel, drying, redistillation), the skill of spotting functional groups in a bigger molecule, and the skill of planning two-stage synthetic routes.

Assumed knowledge: Alkenes, Alcohols, Haloalkanes, Amount of substance (percentage yield).

Core content

Practical skills: Quickfit apparatus for heating under reflux

Quickfit apparatus is glassware with ground-glass joints that fit together tightly without corks or bungs. The same flask, condenser and still head can be rebuilt into different set-ups.

Heating under reflux means heating a reaction mixture with a vertical condenser fitted to the flask. Vapours rise, condense and drip back into the flask, so no volatile reactant or product is lost.

You reflux when a reaction is slow and needs prolonged heating, for example:

  • hydrolysis of a haloalkane with NaOH(aq)
  • oxidation of a primary alcohol all the way to a carboxylic acid
  • making a haloalkane from an alcohol with NaBr/H2SO4
Figure not available yet (chem-reflux-apparatus)

The details examiners check on a reflux diagram:

  • The condenser is vertical and open at the top. A sealed system would build up pressure as it is heated.
  • Cooling water goes in at the bottom and out at the top, so the jacket stays full of water.
  • Anti-bumping granules go in the flask so the liquid boils smoothly, without large violent bubbles.
  • An electric heater (heating mantle or water bath) is used rather than a naked flame, because most organic liquids are flammable.
  • No lines are drawn across the joints between flask and condenser, since a line looks like a seal.

Practical skills: Quickfit apparatus for distillation

Distillation separates a liquid from a mixture by boiling it off, condensing the vapour and collecting it in a separate flask. It works because the components have different boiling points.

Figure not available yet (chem-distillation-apparatus)

The details that earn the marks:

  • The thermometer bulb is level with the side-arm of the still head, so it reads the temperature of the vapour entering the condenser, not of the boiling liquid.
  • The condenser slopes down towards the collecting flask, with water in at the lower end.
  • The collecting end is not sealed to the condenser.
  • You collect the liquid that distils over a narrow range close to the product's boiling point.
Heating under refluxDistillation
Condenser positionvertical, above the flasksloping, leading away from the flask
What happens to the vapourcondenses and returns to the flaskcondenses and is collected separately
Used forprolonged heating of a slow reaction without losing volatile substancesremoving a product as it forms, or separating a liquid product after a reaction
Example from 4.2.1primary alcohol to carboxylic acid (excess oxidising agent)primary alcohol to aldehyde (distil off as it forms)

Practical skills: preparing and purifying an organic liquid

A crude organic liquid straight from a reaction is contaminated with water, acid, unreacted starting material and by-products. Purification removes each one in turn.

  1. Separating funnel. Shake the crude product with an aqueous solution, let the two immiscible layers settle, then run off the layers through the tap and keep the organic layer.
  2. Washing. Shaking with sodium hydrogencarbonate solution neutralises acid impurities. It produces CO2, so invert the funnel and open the tap regularly to release the pressure.
  3. Drying. Run the organic layer into a dry conical flask and add an anhydrous salt such as anhydrous MgSO4 or anhydrous CaCl2. It absorbs the water left dissolved in the organic liquid. The liquid turns from cloudy to clear when it is dry.
  4. Decant (pour off) or filter the dried liquid away from the solid drying agent.
  5. Redistillation. Distil the dried liquid again and collect only the fraction boiling close to the product's boiling point. This separates the product from other organic impurities, such as unreacted starting material, which have different boiling points.
Figure not available yet (chem-separating-funnel)

Which layer is which? The denser liquid sinks to the bottom. Many organic liquids are less dense than water and float on top, but not all: haloalkanes containing bromine or iodine are often denser than water, so they form the lower layer. Check the density, or add a few drops of water and see which layer grows.

Still don't get it? · what each purification step removes

Think of cleaning a muddy pair of trainers before putting them away. You rinse off the mud, then wipe off the soapy water, then leave them to dry, then pick off the last few bits of grit by hand. Each step removes a different kind of dirt, and none of the steps would do the whole job alone.

Purifying an organic liquid works the same way:

  1. The crude liquid contains four kinds of "dirt": acid, other water-soluble impurities, dissolved water, and other organic compounds.
  2. Shaking with an aqueous solution in a separating funnel washes out anything that dissolves in water. Sodium hydrogencarbonate also reacts with the acid.
  3. Separating the layers removes the aqueous solution, but a little water is still dissolved in the organic layer. That is why it looks cloudy.
  4. The anhydrous salt soaks up that last water. Now the liquid is clear.
  5. Organic impurities mix completely with the organic product, so washing with water cannot remove them. Only their different boiling points can separate them, which is what redistillation uses.

In exam wording: the separating funnel removes the aqueous layer; NaHCO3 neutralises acid; the anhydrous salt (MgSO4 or CaCl2) dries the organic layer; redistillation collects the product at its boiling point, separating it from organic impurities.

PAG5: synthesis of an organic liquid

PAG5 is OCR's practical activity group for making and purifying an organic liquid. The spec's example is the synthesis of a haloalkane, and it covers heating under reflux, purification using a separating funnel, distillation and a risk assessment.

A typical example is making 1-bromobutane from butan-1-ol, using the substitution reaction from 4.2.1. Sodium bromide and sulfuric acid make HBr in the flask, and the HBr substitutes for the OH group:

NaBr + H2SO4 → NaHSO4 + HBr

CH3CH2CH2CH2OH + HBr → CH3CH2CH2CH2Br + H2O

StageWhat you doWhy
1. ReactHeat butan-1-ol with NaBr and concentrated H2SO4 under reflux, with anti-bumping granulesthe reaction is slow; reflux allows long heating without losing volatile butan-1-ol or 1-bromobutane
2. SeparateRearrange the apparatus and distil off the crude 1-bromobutaneseparates the organic product from the non-volatile salts and acid left in the flask
3. WashShake the distillate in a separating funnel with water, then with NaHCO3(aq), releasing the pressure; keep the organic layer each timeremoves water-soluble impurities and neutralises acid
4. DryAdd anhydrous CaCl2 or anhydrous MgSO4 until the liquid is clear, then decantremoves dissolved water
5. RedistilDistil again and collect the fraction boiling close to 102 °Cseparates 1-bromobutane from organic impurities such as unreacted butan-1-ol (boiling point 118 °C)

Two things that catch students out in this prep:

  • 1-bromobutane is denser than water (about 1.27 g cm-3), so in the separating funnel it is the lower layer.
  • A risk assessment matters: concentrated sulfuric acid is corrosive, and the organic liquids are flammable, so heat electrically and keep the apparatus open to the air.

Synthetic routes: identifying functional groups

Functional group: a group of atoms responsible for the characteristic reactions of a compound.

In a molecule with several functional groups, find each group first. You are expected to recognise every functional group met in Module 4:

Functional groupStructureHomologous seriesName ending or prefix
alkeneC=Calkenes-ene
hydroxyl-OHalcohols-ol (or hydroxy-)
halogenC-X (X = F, Cl, Br, I)haloalkanesfluoro-, chloro-, bromo-, iodo-
aldehyde-CHOaldehydes-al
ketoneC=O between two carbonsketones-one
carboxyl-COOHcarboxylic acids-oic acid

For an alcohol or a haloalkane, also decide whether it is primary, secondary or tertiary, because that changes what it can do. A tertiary alcohol, for example, cannot be oxidised by acidified dichromate.

Figure not available yet (chem-1-chloropent-4-en-2-ol-functional-groups)

Synthetic routes: predicting properties and reactions

Once you have found the groups, treat each functional group as reacting in the way you already know, with the reagents you know for it. Groups that have no reaction with a reagent are left unchanged.

For 1-chloropent-4-en-2-ol, CH2=CHCH2CH(OH)CH2Cl:

Reagent and conditionsGroup that reactsOrganic productWhat you see or deduce
Br2, room temperatureC=C (addition)CH2BrCHBrCH2CH(OH)CH2Clbromine is decolourised (orange to colourless)
H2, Ni catalyst, about 150 °CC=C (addition)CH3CH2CH2CH(OH)CH2Cl
K2Cr2O7/H2SO4, heat under refluxsecondary alcohol (oxidation)CH2=CHCH2COCH2Cl, a ketoneorange to green
NaOH(aq), heat under refluxC-Cl (nucleophilic substitution)CH2=CHCH2CH(OH)CH2OH

Properties can be predicted the same way. The -OH group can hydrogen bond, so this compound is less volatile and more soluble in water than a hydrocarbon of similar size.

Synthetic routes: the Module 4 reaction toolkit

These are all the transformations between functional groups that you know at this point in the course. Learn the reagents and the conditions for each: in a route question, both are usually needed.

FromToReagents and conditionsType of reactionFrom
alkanehaloalkaneCl2 or Br2, UV radiationradical substitution4.1.2
alkenealkaneH2, nickel catalyst, about 150 °Caddition4.1.3
alkenedihaloalkaneCl2 or Br2, room temperatureelectrophilic addition4.1.3
alkenehaloalkaneHCl or HBr, room temperatureelectrophilic addition4.1.3
alkenealcoholsteam, H3PO4 acid catalyst (high temperature and pressure)addition (hydration)4.1.3
alcoholalkeneacid catalyst (e.g. conc. H3PO4 or conc. H2SO4), heatelimination (dehydration)4.2.1
alcoholhaloalkaneNaBr/H2SO4 (forms HBr), heatsubstitution4.2.1
haloalkanealcoholNaOH(aq) or KOH(aq), heat under refluxnucleophilic substitution (hydrolysis)4.2.2
primary alcoholaldehydeK2Cr2O7/H2SO4, heat, distil off the aldehyde as it formsoxidation4.2.1
primary alcoholcarboxylic acidexcess K2Cr2O7/H2SO4, heat under refluxoxidation4.2.1
secondary alcoholketoneK2Cr2O7/H2SO4, heat under refluxoxidation4.2.1
Figure not available yet (chem-ocr-as-synthesis-map)

Gaps and dead ends in the Module 4 toolkit, which shape your routes:

  • No one-step route from a haloalkane to an alkene. Go via the alcohol: haloalkane → alcohol → alkene.
  • Ketones and carboxylic acids are end points at this stage. Their further reactions come in Module 6.
  • An aldehyde is only an end point or a stop on the way to the acid. Oxidising an isolated aldehyde is A level content (6.1.2).
  • Tertiary alcohols cannot be oxidised.
  • None of these reactions changes the carbon skeleton, so the start and target have the same number of carbon atoms in the same arrangement.
  • Radical substitution is a poor way to make a specific haloalkane: it gives a mixture of products, by further substitution and by substitution at different positions in the chain. Make haloalkanes from an alkene (with HX) or an alcohol (with NaBr/H2SO4) instead.

The exam may give you extra information about a reaction you have not met. Treat it as one more arrow in the toolkit and use it in the route.

Synthetic routes: devising a two-stage route

A two-stage route converts a starting compound into a target through one intermediate. Work through it like this:

  1. Identify the functional group in the starting compound and in the target.
  2. Check the carbon skeleton is the same. It must be, with this toolkit.
  3. Work backwards from the target: which functional group can be turned into the target in one step?
  4. Check forwards: can the starting compound be turned into that intermediate in one step?
  5. For each stage, write the reagents, the conditions, and the name or structure of the intermediate. Add equations if they are asked for.
Still don't get it? · working backwards to plan a route

Imagine planning a train journey from your town to a city with no direct train. You would not pick a train at random and hope. You look at the city first, find which stations have a direct train into it, and then check which of those stations you can reach directly from home. That station is where you change.

A synthesis route is the same idea:

  1. The target is the city. The starting compound is home.
  2. The toolkit table is the timetable: each row is one direct train between two functional groups.
  3. Look up every row that ends at the target's functional group. Each one gives a possible "change station" (intermediate).
  4. For each possible intermediate, look for a row that starts at your starting compound's functional group and ends at it.
  5. The intermediate that appears in both lists is your route. If none does, you need more than two stages, or the exam has given you an extra reaction to use.

For example, to turn 1-bromopropane into propanal: the only row ending in an aldehyde starts from a primary alcohol. Can 1-bromopropane become propan-1-ol in one step? Yes, by hydrolysis. So the intermediate is propan-1-ol.

In exam wording, give each step's reagent, conditions and the intermediate: "Stage 1: NaOH(aq), heat under reflux, forms propan-1-ol. Stage 2: K2Cr2O7/H2SO4, heat and distil, forms propanal."

Worked examples

1. Two-stage route: 1-bromopropane to propanal

Plan. Target: aldehyde. Only a primary alcohol gives an aldehyde, so the intermediate is propan-1-ol. 1-bromopropane is a haloalkane, and haloalkanes hydrolyse to alcohols. Both stages exist, and the carbon chain stays at three carbons.

Stage 1: NaOH(aq), heat under reflux. Intermediate: propan-1-ol.

CH3CH2CH2Br + NaOH → CH3CH2CH2OH + NaBr

Stage 2: K2Cr2O7/H2SO4, heat and distil off the propanal as it forms.

CH3CH2CH2OH + [O] → CH3CH2CHO + H2O

Where marks go: "distil" is the condition that stops the oxidation at the aldehyde. Writing "heat under reflux" here gives propanoic acid instead, and loses the mark.

2. Two-stage route: ethene to ethanoic acid

Plan. Target: carboxylic acid. It comes from a primary alcohol with excess oxidising agent under reflux, so the intermediate is ethanol. Ethene becomes ethanol by hydration.

Stage 1: steam with an H3PO4 catalyst (high temperature and pressure). Intermediate: ethanol.

CH2=CH2 + H2O ⇌ CH3CH2OH

Stage 2: excess K2Cr2O7/H2SO4, heat under reflux.

CH3CH2OH + 2[O] → CH3COOH + H2O

Check the [O] count: going from CH3CH2OH to CH3COOH removes 2 H (as water) and adds 1 O, which needs 2[O].

3. Two-stage route: cyclohexanol to 1,2-dibromocyclohexane

Plan. Target: a dihaloalkane with the two Br atoms on neighbouring carbons. That pattern comes from adding Br2 across a C=C, so the intermediate is cyclohexene. An alcohol becomes an alkene by elimination of water.

Stage 1: acid catalyst (conc. H3PO4 or conc. H2SO4), heat. Intermediate: cyclohexene.

C6H11OH → C6H10 + H2O

Stage 2: Br2 at room temperature.

C6H10 + Br2 → C6H10Br2

Why not NaBr/H2SO4 on the alcohol? That swaps OH for one Br, giving bromocyclohexane, not the dibromo compound.

4. Percentage yield of a prepared liquid

This uses the percentage yield method from Amount of substance, applied to the PAG5 preparation.

Task: 7.40 g of butan-1-ol is converted into 1-bromobutane using excess NaBr and H2SO4. After purification, 6.50 cm3 of 1-bromobutane is collected. The density of 1-bromobutane is 1.27 g cm-3. Calculate the percentage yield.

C4H9OH + HBr → C4H9Br + H2O (1 : 1 ratio)

Step 1: molar masses (relative atomic masses from the data sheet).

M(C4H9OH)=(4×12.0)+(10×1.0)+16.0=74.0 g mol−1M(\text{C}_4\text{H}_9\text{OH}) = (4 \times 12.0) + (10 \times 1.0) + 16.0 = 74.0 \text{ g mol}^{-1}

M(C4H9Br)=(4×12.0)+(9×1.0)+79.9=136.9 g mol−1M(\text{C}_4\text{H}_9\text{Br}) = (4 \times 12.0) + (9 \times 1.0) + 79.9 = 136.9 \text{ g mol}^{-1}

Step 2: amount of the limiting reagent. The other reagents are in excess, so butan-1-ol sets the maximum yield.

n(C4H9OH)=7.40 g74.0 g mol−1=0.100 moln(\text{C}_4\text{H}_9\text{OH}) = \frac{7.40 \text{ g}}{74.0 \text{ g mol}^{-1}} = 0.100 \text{ mol}

Step 3: theoretical mass of product (1 : 1 ratio, so 0.100 mol of 1-bromobutane).

mtheoretical=0.100 mol×136.9 g mol−1=13.69 gm_{\text{theoretical}} = 0.100 \text{ mol} \times 136.9 \text{ g mol}^{-1} = 13.69 \text{ g}

Step 4: actual mass from the volume collected.

mactual=6.50 cm3×1.27 g cm−3=8.255 gm_{\text{actual}} = 6.50 \text{ cm}^3 \times 1.27 \text{ g cm}^{-3} = 8.255 \text{ g}

Step 5: percentage yield.

percentage yield=8.255 g13.69 g×100=60.3%\text{percentage yield} = \frac{8.255 \text{ g}}{13.69 \text{ g}} \times 100 = 60.3\%

The data are all to 3 significant figures, so the answer is given to 3 significant figures: 60.3%.

Where marks are dropped:

  • Using the volume (6.50) as if it were a mass. Convert with density first: mass = volume × density.
  • Working from the moles of NaBr or H2SO4. They are in excess, so they do not limit the yield.
  • Dividing the wrong way up. Theoretical ÷ actual gives 166%, and a yield above 100% is impossible, so it is a quick check.

Common exam mistakes

  • Drawing the reflux condenser sealed at the top, or with a bung in it. It must be open; heating a sealed system builds up pressure.
  • Water in at the top of the condenser. Water goes in at the bottom and out at the top.
  • Thermometer bulb in the liquid during distillation. It goes level with the side-arm, to read the temperature of the vapour being collected.
  • Explaining reflux as "to stop it boiling over" or just "to heat it". Say the vapours condense and return to the flask, so the mixture can be heated for a long time without losing volatile reactants or products.
  • Assuming the organic layer is always on top. The denser layer is at the bottom; bromo- and iodoalkanes such as 1-bromobutane are often denser than water.
  • Forgetting to release the pressure when washing with NaHCO3(aq). It produces CO2.
  • Writing "MgSO4 solution" as the drying agent. It must be the anhydrous solid. The sign that the liquid is dry is that it turns clear.
  • Saying redistillation "removes water". The drying agent removes water; redistillation separates the product from organic impurities by collecting it at its boiling point.
  • Giving a reagent without its conditions in a route, e.g. "K2Cr2O7" with no acid and no "distil" or "reflux", or "NaOH" without aqueous and reflux.
  • Mixing up distil and reflux for oxidation: distil for the aldehyde, reflux (with excess oxidising agent) for the carboxylic acid or the ketone.
  • Not naming the intermediate. A two-stage route needs the compound made in stage 1, by name or structure.
  • Oxidising a tertiary alcohol in a route. Tertiary alcohols do not react with acidified dichromate.
  • Choosing radical substitution of an alkane to make one particular haloalkane. It gives a mixture of products; use an alkene with HX, or an alcohol with NaBr/H2SO4.
  • Changing the number of carbon atoms between start and target. None of the reactions in the toolkit table makes or breaks a C-C bond in the chain.

Key definitions

  • Functional group: a group of atoms responsible for the characteristic reactions of a compound.
  • Heating under reflux: heating a mixture with a vertical condenser so that vapours condense and return to the flask, allowing prolonged heating without loss of volatile substances.
  • Distillation: heating a mixture so that a volatile component boils off, is condensed and is collected separately.
  • Redistillation: distilling a crude product a second time and collecting only the fraction that boils close to the product's boiling point, to separate it from organic impurities.
  • Quickfit apparatus: glassware with ground-glass joints that fit together without bungs, so it can be assembled for reflux or distillation.
  • Immiscible: describes two liquids that do not mix, so they form separate layers.
  • Drying agent: an anhydrous salt (e.g. MgSO4 or CaCl2) that removes water from an organic liquid.
  • Two-stage synthetic route: a sequence of two reactions that converts a starting compound into a target compound through one intermediate.

Specification

  • I can draw and label Quickfit apparatus for heating under reflux and for distillation, and explain when each is used. (4.2.3 a i)
  • I can describe how to use a separating funnel to remove an organic layer from an aqueous layer, and decide which layer is which from density. (4.2.3 a ii)
  • I can describe drying an organic liquid with an anhydrous salt (e.g. MgSO4, CaCl2), and how to tell when it is dry. (4.2.3 a ii)
  • I can explain why the product is redistilled and which fraction is collected. (4.2.3 a ii)
  • I can outline the preparation and purification of an organic liquid such as a haloalkane, giving a reason for each step. (4.2.3 a, PAG5)
  • I can identify every Module 4 functional group in a molecule that contains several of them. (4.2.3 b i)
  • I can predict the properties and the reactions of a molecule with several functional groups, including which group reacts with a given reagent. (4.2.3 b ii)
  • I can devise a two-stage synthetic route between Module 4 functional groups, giving reagents, conditions and the intermediate, and use extra reactions given in a question. (4.2.3 c)

now prove it

Try Organic synthesis questions, marked against the full mark scheme.